(5/3x)^2-x+(17/6)=0

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Solution for (5/3x)^2-x+(17/6)=0 equation: 



(5/3x)^2-x+(17/6)=0



Domain of the equation: 3x)^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/3x)^2-x+(+17/6)=0

We add all the numbers together, and all the variables

-1x+(+5/3x)^2+(+17/6)=0

We get rid of parentheses

-1x+(+5/3x)^2+17/6=0

We calculate fractions


-1x+()/3x^2*6)+51x/3x^2*6)=0

We can not solve this equation

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